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every vertex has a minimum degree, therefore, least number of edges that will be in the graph is given by the handshaking lemma as = min×|v|/2=2 E is right?

 

 

asked in Graph Theory by Active (1.6k points)   | 25 views

$\delta \leqslant \frac{2e}{v}\leq \Delta$.

Here $\delta$ is minimum degree and $\Delta$ is maximum degree.

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