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f(x) = x^ (-1/3)

Show that f(x) is

  • not countinuous  in [-1,1] and
  • not bounded [-1,1]
asked in Calculus by Active (2.4k points)   | 41 views
As x->0 from positive side, f(x) approaches infinity. As value of 'x' increases on positive side, f(x)->0

As x becomes negative, f(x) has values on the third axis i.e. z axis or imaginary axis

Certainly, this isnt continous.

Ad isnt bounded as well.

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