1 votes 1 votes Let A can finish the task in 8 days and B can finish the same task in 10 days. How many days are required to finish the task if both are working alternate days.?? --------------------------------------------------------- Ans ;;$8\frac{4}{5}$ days. santhoshdevulapally asked Jan 5, 2017 santhoshdevulapally 497 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply thor commented Jan 5, 2017 reply Follow Share i think answer will vary depending on who started first 0 votes 0 votes santhoshdevulapally commented Jan 5, 2017 reply Follow Share consider A is start first. then explain the problem now? 0 votes 0 votes papesh commented Jan 5, 2017 i moved by papesh Jan 5, 2017 reply Follow Share Total work Needs to Done = LCM(8,10) = 40 units A's one day's work = 40/8 = 5 Unit B's one day's work = 40/10 = 4 Unit Together They can DO 5 + 4 =9 units of work per day (5 + 4 ) * 4 =36 units =8 days Remaining 40-36 =4 unit of work If A start first 4/5 day Here Ans = 8 (4/5 ) days If B start first 4/4 = 1 more day Here Ans = 9 days 1 votes 1 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes Considering the case, A starts first Prabhanjan_1 answered Jan 5, 2017 • selected Jan 5, 2017 by santhoshdevulapally Prabhanjan_1 comment Share Follow See all 0 reply Please log in or register to add a comment.
