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Internal fregmentation will occur in the last frame.

Say i have my Process of 20 kb and my page size is 4kb,then my process will fit nicely in 5 frames.Now if my process is more than 20kb then i have to allocate new frame.Best case will be i will fully use that new frame,and worst case is i will store only 1 byte in that frame.

So maximum internal fregmentation possible is FrameSize-1

In you case it will be 1024-1=1023
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I am getting 1023B because   maximum internal fregmentation possible =  FrameSize - 1

Therefore it will be 1024 -1= 1023B

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