After taking |A|=0, I am getting x^{3}+1=0 and not x^{3}-1=0. Is it x^{3}+1=0 or x^{3}-1=0?
Ya, i missed the '-' in multiplying 2nd parameter.
BTW, expansion of (x^{3}-1) is (x-1)(x^{2}+x+1), so x=1, and not -1, for real values of x.
4768 Points
3054 Points
2920 Points
2728 Points
2602 Points
1572 Points
1422 Points
1362 Points
1334 Points
1126 Points
Gatecse