After taking |A|=0, I am getting x^{3}+1=0 and not x^{3}-1=0. Is it x^{3}+1=0 or x^{3}-1=0?
Ya, i missed the '-' in multiplying 2nd parameter.
BTW, expansion of (x^{3}-1) is (x-1)(x^{2}+x+1), so x=1, and not -1, for real values of x.
4654 Points
4020 Points
3136 Points
2832 Points
2644 Points
2370 Points
2040 Points
1742 Points
1574 Points
1554 Points
Gatecse
Yeah ! Of course.IT people are also ...