After taking |A|=0, I am getting x^{3}+1=0 and not x^{3}-1=0. Is it x^{3}+1=0 or x^{3}-1=0?
Ya, i missed the '-' in multiplying 2nd parameter.
BTW, expansion of (x^{3}-1) is (x-1)(x^{2}+x+1), so x=1, and not -1, for real values of x.
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Book name : Russell and Norvig. ...