simple, just take the reflexive closure by adding the diagonal elements and then take the transitive closure and verify with the options.
S={(0,1),(1,2)}
reflexive closure of S={(0,0), (1,1), (2,2,) ,(0,1),(1,2)}
Now take transitive closure={(0,0), (1,1), (2,2,) ,(0,1),(1,2),(0,2)}
clearly x<=y.