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An ordinary deck of 52 playing cards is randomly decoded into 4 piles of 13 cards each. The probability that each pile has exactly 1 ace is
asked in Mathematical Logic by Active (1.8k points)   | 66 views

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Just imagine that 4 aces are in different piles and then follow this approach:

answer

= $\frac{\binom{48}{12}*\binom{36}{12}*\binom{24}{12}*\binom{12}{12}*4!}{\binom{52}{13}*\binom{39}{13}*\binom{26}{13}*\binom{13}{13}}$

$\approx 0.105$

answered by Veteran (15.1k points)  

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