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#include

int main()

{

char *x;

x = (char *) &a;

a = 512;

x[0] = 1;

x[1] = 2;

printf("%d\n",a);

return 0;

}

What is the output of above program?

(a) Machine dependent

b) 513

(c) 258

(d) Compiler Error
Obvio it will be compilation error , you are using undeclared a
............................

+1 vote

Assuming a is declared first.

• In a system that uses little-endian (Like  Intel x86 processors ) the answer should be $513$
• In a system that uses big-endian (Like IBM z/Architecture mainframes ) the answer should be a very large value.

Answer should be (a) Machine dependent

debashish,how do u know that it is endian notation??
and if  'a' is a int variable then how will x[0] and x[1] work??

i mean a is an integer type variable,so what will be x[0] or x[1] refer to??

@Akriti

A prerequisite to know what is happening http://gateoverflow.in/4273/char-pointer-to-access-an-int

thanks @kapil..

+1 vote