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asked in Computer Networks by Active (1.3k points)   | 22 views

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Ans is 100.......What's the catch here.....

See first 20 frames are being transmitted which has 0.8 chance off ariving undamaged......

so 20+20*0.8=20+16=36 frames arrived undamaged.....

now out of 16 also 0.8 are transmitted successfully......i.e; 16*0.8=12.8

therefore.....36+12.8=48.8

now for again 12.8 frames do the same thing......It's very hectic(It's for understanding)

so generally for n frames with p probability of transmitting undamaged is.....

n+np+np^2+p^3......

n(1+p+p^2+p^3.......)

n(1/(1-p)).....(infinite GP with a=1 and r=p)

now n=20 and p=0.8 given

so n(1/(1-p))=20/0.2=100

so 100 frames are transmitted....
answered by Active (1.2k points)  

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