GATE CSE
First time here? Checkout the FAQ!
x
0 votes
24 views

asked in Computer Networks by Active (1.3k points)   | 24 views

1 Answer

0 votes
Ans is 100.......What's the catch here.....

See first 20 frames are being transmitted which has 0.8 chance off ariving undamaged......

so 20+20*0.8=20+16=36 frames arrived undamaged.....

now out of 16 also 0.8 are transmitted successfully......i.e; 16*0.8=12.8

therefore.....36+12.8=48.8

now for again 12.8 frames do the same thing......It's very hectic(It's for understanding)

so generally for n frames with p probability of transmitting undamaged is.....

n+np+np^2+p^3......

n(1+p+p^2+p^3.......)

n(1/(1-p)).....(infinite GP with a=1 and r=p)

now n=20 and p=0.8 given

so n(1/(1-p))=20/0.2=100

so 100 frames are transmitted....
answered by Active (1.3k points)  

Related questions

0 votes
1 answer
1
asked ago in Computer Networks by hem chandra joshi Junior (605 points)   | 12 views
0 votes
1 answer
2
asked ago in Computer Networks by hem chandra joshi Junior (605 points)   | 19 views
0 votes
1 answer
3


Top Users Jul 2017
  1. Bikram

    3960 Points

  2. manu00x

    2464 Points

  3. Debashish Deka

    1848 Points

  4. joshi_nitish

    1654 Points

  5. Arjun

    1290 Points

  6. Hemant Parihar

    1184 Points

  7. Arnab Bhadra

    1100 Points

  8. Shubhanshu

    1052 Points

  9. Ahwan

    900 Points

  10. rahul sharma 5

    702 Points


24,018 questions
30,955 answers
70,326 comments
29,337 users