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switch case output in case of expressions

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1 votes
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#include

int main()

{ char check = 'a';

switch (check)

{

case 'a' || 1: printf("Gates ");

case 'b' || 2: printf("Quiz ");

break;

default: printf("GatesQuiz");

} return 0; }

(a) Gates

(b) Gates Quiz

(c) Gates Quiz GatesQuiz

(d) Compile-time error
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2 Answers

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i think  ryt option is "D" bcoz 'a'||1 will evaluate to 1 and 'b'||2 will also evaluate to 1 so both the case will become same .

and in swicth case every case must be unique so it will generate compile time error.
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The integral expressions used in labels must be a constant expressions.

The cases are labeled with characters which gets converted to their ascii values 97(for a) and 98(for b).

Now 97 OR with 1 will give 1 as TRUE OR TRUE is TRUE. Similar for 2nd case.

Two case labels cannot have same value therefore gives compile time error.

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