0 votes 0 votes we know jhonson counter does mod(2N) counting and ring does mod(N) counting with N no. of FF's then can some one tell about ripple counter.....is it mod(2^N)??? cse23 asked Jan 16, 2017 cse23 267 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes in johnson counter with n flipflop we have 2n states . in ripple counter with n flip flops we have 2n states . in ring counter with n flipflop we have n states . focus _GATE answered Jan 16, 2017 • selected Jan 18, 2017 by focus _GATE focus _GATE comment Share Follow See 1 comment See all 1 1 comment reply cse23 commented Jan 16, 2017 reply Follow Share thnx:) 1 votes 1 votes Please log in or register to add a comment.
