Two schedules S1 and S2 are said to be view-equivalent when the following conditions are satisfied:
- If the transaction $T_i$ in S1 reads an initial value for object X, so does the transaction $T_i$ in S2.
- If the transaction $T_i$ in S1 reads the value written by transaction $T_j$ in S1 for object X, so does the transaction $T_i$ in S2.
- If the transaction $T_i$ in S1 is the final transaction to write the value for an object X, so is the transaction $T_i$ in S2.
source: Wikipedia
$T_3$ performs the final write on the data item $A$, thus any view equivalent serial schedule must execute $T_3$ after other two transactions.
From the given options, only (1) propose a serial schedule which has $T_3$ after $T_1$ and $T_2$. Thus, option (1) is right answer.
HTH