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C programming

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global int i = 100, j = 5;

void P(x)

{

    int i = 10;

    print(x + 10);

    i = 200;

    j = 20;

    print(x);

}

main()

{

    P(i + j);

}

If the programming language uses dynamic scoping and call by name parameter passing mechanism, the values printed by the above program are :
(A) 115, 220
(B) 25, 220
(C) 25, 15
(D) 115, 105

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1 Answer

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due to dynamic scoping the second  print will give 200+20 =220

and as per the first print by defintion of call  by name "the parameter is evaluated when it is used not when passed"  so x will be evaluted into the P(X) so it be x=10+5   then print(x+10) will be 25

so and will  be (B)
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