305 views
0 votes
0 votes

2 Answers

0 votes
0 votes
As nothing mentioned so take it as Class C, as class C ranges from 192-223, So Network ID 154.33.7.192, Subnet bits- 2 bits, Host Id contains last 6 bits.
0 votes
0 votes

MASK 255.255.255.192

IP       154.33.7.220


           154.23.7.192 (NETWORK ID )
 


from mask we know 255.255.255.11 000000

000000 these are host bits so there are 6 subnets bits 
11 will be subnet bits so there are 2 subnet bits

Related questions

3 votes
3 votes
2 answers
2
HeartBleed asked Feb 4, 2019
1,971 views
A network with three hosts M, N and P have IP address 194.56.10.2, 194.56.10.5 and194.56.10.6 and their subnet mask is 255.255.255.252. Which of the following will bein a...
1 votes
1 votes
1 answer
3
rahuljai asked Dec 15, 2018
1,214 views
What’s the right answer ?, please have a look at Q.5(here) they are appending network bits but this question doesn't.
0 votes
0 votes
1 answer
4
radha gogia asked Apr 23, 2018
997 views
A ) 255.255.(28-M -1) * 2M .0B) 255.255.(28-M )* 2M .0Please explain precisely .