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CN DOUBT - CONGESTION WINDOW

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If the present windows size at receiver is 8000byte. Each mss is 2000 byte and no. Of acknowledgemt during that time are 2.  What is present window size if congestion avoidance algo. Is used.
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In collision Avoidance

after getting one acknowledgement window size got increased by 1mss

here two acknowledgement received

so it must got increased by 2mss

=8000+2mss -> 8000+2000+2000  ->  12000 bytes

please correct me ? if i am wrong
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slow start: TCP start with 1 MSS and on each ack congestion window is increased by 1 MSS(Exponential increase).

you not given your slow start threshold value so how we when we enter congestion avoidence phase.

 

reciver window is not the current window size of sender because send window=min(cwnd,rec_winodw).

your question seems incomplete.
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