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In a particular number system the cubic equation X^3+bX^2+cX-190 has roots 5,8 and 9.What is the base of the no system?

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X^3+bX^2+cX-190=(X-5)(X-8)(X-9)

                             =X^3-(17+5)X^2+(72+85)X-360

NOW,   b=-(17+5)  and  c=(72+85)

take b=-26 and  c=235 and let base is y.

after solving in both case base is 8.

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