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Answer should be -128.

Overall size of Instruction is : 24 bit.

There are 32 register , so to represent 32 register we need 5 Bit.

There are 49 instruction , so we need 6 bit to represent all instructions.

so, immediated operand: 24-6+2*5 = 8

so minimum number thatw e  can represent with 8 bits is -(2^n-1) = -128
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