output

Question

#include <stdio.h>
void f(int x,int *p)
{
    *p=x;
    x=10;
}
int main()
{
    int a=5,b=6;
    int *p=&a,**q;
    *p=20;
    q=&p;
    f(a,&b);
    *q=&b;
    *p=30;
    printf("%d",b);
}

How the answer is 30 I am getting 20?

Answer 1

See  last 3 lines of main() function

 

q is pointing to p

*q = &b implies that now p is pointing to b

*p= 30

Implies contents of variable b now modified to 30

Comments

there is a function call in between , so you are saying wrong.

anyways still the answer has to be 30 , but i am confused how.

---

Surely theres a func call but final value of b is decided by last 3 lines only.

See,

20 and address of b is passed

Now, in  function f x=20 and p is pointing to b

*p=x

Implies that now b is modified with value if x i-e 20

Now return to main

*q= &b

q pointing to p so *q means p

p=&b

So now p points to b

And *p=30

Means b value is modified to 30.

 

Now tell at which point your are confusing?

---

I got it bro...

It was clever though ! Thanks!!