A/c :
h1 = 0.9 , h2 = 0.95 , t1 = 1ns , t2 = 5ns , t3 = 50ns
There are Two Types of Memory Leveling:
Acess in Parallel : --
EAT = h1*t1 + (1-h1)*h2*t2 + (1-h1)*(1-h2)*t3
= 0.9*1 +0.1*0.95*5 + 0.1*0.05*50
= 1.625
Not Acess in Parallel : --
EAT = h1*t1 + (1-h1)*h2*(t1+t2) + (1-h1)*(1-h2)*(t1+t2+t3)
= 0.9*1 + 0.1*0.95*(1+5) + 0.1*0.05*(1+5+50)
= 1.75
Hence both Answer is Correct bcz in this question not mention which process is Apply.