0 votes 0 votes #plz check i got 21 ??? but answer is 86 Mathematical Logic testbook-test-series test-series + – Hradesh patel asked Jan 26, 2017 • retagged Jun 4, 2017 by Arjun Hradesh patel 477 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Hradesh patel commented Jan 26, 2017 reply Follow Share ............................. 0 votes 0 votes Sankalp20894 commented Jan 26, 2017 reply Follow Share the problem is together not together first put 6 1's it create 7 slot select any 4 slot fronm them to put 0's 6!/6!*7C4=35 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes The necessary condition to be satisfied is: 0 1 0 1 0 1 0 Now, there are remaining three 1's that need to be placed: _ 0 _ 0 _ 0 _ 0 _ Now, its like placing 3 identical balls into 5 different boxes. That can be done in (5+3-1)C3 ways = 35 ways Sushant Gokhale answered Jan 26, 2017 • selected Feb 1, 2017 by Prajwal Bhat Sushant Gokhale comment Share Follow See 1 comment See all 1 1 comment reply Prateek Yadav 2 commented Jan 26, 2017 reply Follow Share yes i m also geting 35 1 votes 1 votes Please log in or register to add a comment.