1 votes 1 votes shubhamdarokar asked Jan 27, 2017 shubhamdarokar 308 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply shubhamdarokar commented Jan 27, 2017 reply Follow Share can any1 plz tell me how to approach such questions 0 votes 0 votes akshay_845 commented Jan 27, 2017 reply Follow Share is 105 the answer 0 votes 0 votes shubhamdarokar commented Jan 27, 2017 reply Follow Share no its 10 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes x1+x2+x3=8 where x1>=3,x2>=-2,x3>=4 x1+x2+x3=8 - 5=3 with x1>=0,x2>=0,x3>=0 No.of integrals solutions=(n+r-1)Cr=(3+3-1)C3=5C3=10 Ans :10 Arnabi answered Jan 27, 2017 selected Jan 27, 2017 by shubhamdarokar Arnabi comment Share Follow See all 0 reply Please log in or register to add a comment.