for L1:- 1/4*60*60=900 miss
because at every 4 elements in cache block 1 (MISS)
as when the program wants to print value searches value in the cache memory as it does not find(MISS) so it takes consecutive 16 byte means 4 elements and put inside block so for other three (HIT) now again same others.
for L2: -program prints from last so we can not put 16 bytes at a time so MISS for all elements 60*60=3600 (MISS)