ACE test series

Question

Answer 1

There is no break inside switch. So all cases will execute.

We enter the switch with i=0 and come out with i=16. 

Print=> 16

Now second iteration will begin. 16<20 evaluates to true. So i becomes 17. 

This time, only default case will execute. So i = 17+4= 21

Print=> 21

Comments

I am still not getting that why the second iteration will execute only default statement

Answer 2

1.First of all expression inside switch will be executed, i.g, switch(<expression>).

2. Now the value of this expression will be matched with 'case' blocks. If no match then 'default' block will be chosen.

3. If we will not use 'break' statement then the following 'case' blocks or 'default' block will also get executed untill it encounters first 'break' or end of the 'switch' block.

Now in this question:

Initially, i=0.

Case 0, will execute first. It will make i=5. Since there is no 'break' statement, so the following cases will also get executed, making 'i' value to 7,  12 and at the end 16(default case). So in 1st iteration 16 will get printed.

Now in 'for' loop, i= 17, only deafult case will execute , now i=21. So 21 will get printed.

It will terminate the 'for' loop.

I think this is the main concept !! correct if I am wrong.