0 votes 0 votes iita asked Jan 30, 2017 iita 773 views answer comment Share Follow See all 22 Comments See all 22 22 Comments reply Show 19 previous comments sudsho commented Jan 30, 2017 reply Follow Share ^ these 2 statements are always true....if 88 was not divided further then 88 was a fragment initially fr some other packet fr which these conditions will hold.... without these 2 statements u cant do reassembling of fragments 0 votes 0 votes iita commented Jan 30, 2017 reply Follow Share let's say 88 is the first fragment and it's not divided further so no databytes are ahead of it hence it's offset will be 0(since first packet) but the packet following 88 will have offset as 88..correct me if I am wrong 0 votes 0 votes sudsho commented Jan 30, 2017 reply Follow Share but the packet following 88 will have offset as 88 i already told u offset means no of databytes ahead of that particular fragment ...if packet is not fragmented then why previous packet of 88 will have offset as 88? we fragment a packet into fragments and give offset, MF etc to particular fragments of that packet....how fragments of a packet are identified?...using IDENTIFICATION no...please read fragmentation again u'll get it.. 0 votes 0 votes Please log in or register to add a comment.