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2 Answers

2 votes
2 votes
Option A is correct as L is Decidable, its complement will also be decidable.
–1 votes
–1 votes

option B is correct

1)   if L is an NP-class then L(M) is UNDECIDABLE 

 because the COMPLETENESS problem is always in TM , that means L is RECURSIVELY ENUMARABLE 

2)  As L is RECURSIVELY ENUMARABLE ,its doent allow MEMBERSHIP ALGORITHM so it is also

UNDECIDABLE 

but LANGUAGES ARE not closed under complementation in RE languages

i am sry i dont think the answer  was B i am wrong

i think mostly  4 or 3

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