2 votes 2 votes iita asked Jan 31, 2017 iita 3.3k views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments iita commented Jan 31, 2017 reply Follow Share @rahul jain I got 0 coz I applied the concept that.. No. of linearly independent vectors= n-r where n- number of unknowns and r- rank of matrix, here both are 3 rank and number of unknowns..so..got 0..?? 0 votes 0 votes Rahul Jain25 commented Jan 31, 2017 reply Follow Share That is used to get solution in system of equations where AX= 0 , and I think it is not applicable here. 0 votes 0 votes Ghoul7 commented Mar 15, 2020 reply Follow Share the answer is 2 ( linearly independent eigen vectors). For a reapted eigen value here (1,1,1) the number of free variables is equal to. Independent eigen vector 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes eigen value of diagonal matrix or upper tringular matrix is diagonal element itself so eigen vector is 1 RAJESHWAR YADAV answered Jan 31, 2017 RAJESHWAR YADAV comment Share Follow See all 11 Comments See all 11 11 Comments reply Show 8 previous comments Rahul Jain25 commented Feb 1, 2017 reply Follow Share @Sushant. If A is non singular than trivial(zero) unique solution. If |A|=0 or rank is zero then system has non-trivial solution(infinite), now further the number of linearly independent infinite solution is equal to n-r where r is the rank of "A" and n unknowns. 0 votes 0 votes Sushant Gokhale commented Feb 1, 2017 reply Follow Share @Rahul. Just gng to mug up the concept. No time to understand in depth. :P 0 votes 0 votes Rahul Jain25 commented Feb 1, 2017 reply Follow Share Haha. 0 votes 0 votes Please log in or register to add a comment.