3 votes 3 votes closed with the note: out of syllabus Newton-Raphson method is used to compute a root of the equation $x^2 - 13 = 0$ with 3.5 as the initial value. The approximation after one iteration is 3.575 3.676 3.667 3.607 Numerical Methods gatecse-2010 numerical-methods newton-raphson easy non-gate + – gatecse asked Sep 21, 2014 • closed May 11, 2018 by srestha gatecse 6.2k views comment Share Follow See 1 comment See all 1 1 comment reply akash.dinkar12 commented Aug 6, 2018 reply Follow Share follow this one... 1 votes 1 votes Please log in or register to add a comment.
3 votes 3 votes x=3.5 - ((3.5^2)-13)/(2*3.5) so x=3.607 it is from the next term formula of newton raphson method Bhagirathi answered Sep 21, 2014 Bhagirathi comment Share Follow See all 4 Comments See all 4 4 Comments reply anchitjindal07 commented Aug 30, 2017 reply Follow Share What is the formula, Sir? 0 votes 0 votes Bikram commented Aug 31, 2017 reply Follow Share This one http://nptel.ac.in/courses/122104019/numerical-analysis/Rathish-kumar/ratish-1/f3node6.html 0 votes 0 votes anchitjindal07 commented Aug 31, 2017 reply Follow Share I have seen this formula, but it looks like Bhagirathi is using some other formula 0 votes 0 votes Rohan7980 commented Feb 2, 2018 reply Follow Share same formula is used, x1= x0-f(x0)/f'(x0) 0 votes 0 votes Please log in or register to add a comment.