2 votes 2 votes (a) P3, Ps, P3, P2 (b)P2, P5, P3, 426k waits (c)P3, Ps, P2, 426k waits (d)P4, P2, P5, P3 Operating System memory-management + – ManojK asked Feb 4, 2017 ManojK 668 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes Worst Fit: to a coming request one by one ,allocate the chunk where maximum amount of space will be wasted at first 212 K is coming.. worst fit for 212 K is 800K, (p3) remaining 588K then comes 417K and worst fit for this is 600K(p5) then comes 112 K , and worst fit among remaining places is 688K(p3) then comes 426 K now only 500K available so it is worst for it.. so matching we get A is correct answer here Aboveallplayer answered Feb 4, 2017 • selected Feb 4, 2017 by ManojK Aboveallplayer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments ManojK commented Feb 4, 2017 reply Follow Share So according to you default assumption should be Variable size partitioning.rt? 0 votes 0 votes Aboveallplayer commented Feb 4, 2017 reply Follow Share ya .. 1 votes 1 votes Prateek kumar commented Jan 5, 2018 reply Follow Share your answer is right only if we consider this question as "VARIABLE PARTITION" as it's not been mentioned fixed or variable partition 1)using variable partition:- option "A" 2)using fixed partition:- option "C" 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes 100k| 500k | 800k | 300k | 600k | p1 | p2 | p3 | p4 | p5 --------------------------------------------------------------------------------- 212 in p3 100k| 500k |||||||||||| 588k | 300k | 600k | p1 | p2 |||||||||||| p3 | p4 | p5 --------------------------------------------------------------------------------- 417 in p5 100k| 500k |||||||||||| 588k | 300k ||||||||||| 183 | p1 | p2 |||||||||||| p3 | p4 | p5 --------------------------------------------------------------------------------- 112 in p3 100k| 500k ||||||||||||||||||||||||||||476k | 300k |||||||||| 183 | p1 | p2 |||||||||||| p3 | p4 | p5 --------------------------------------------------------------------------------- 426 in p2 so option a Debasmita Bhoumik answered Feb 4, 2017 Debasmita Bhoumik comment Share Follow See all 0 reply Please log in or register to add a comment.