1 indian && (0 or 1 or 2 or 3) chinese = 3C1 × [3C0 + 3C1 + 3C2 + 3C3] = 3 × [8]
2 indian && (0 or 1 or 2 or 3) chinese = 3C2 × [3C0 + 3C1 + 3C2 + 3C3] = 3 × [8]
3 indian && (0 or 1 or 2 or 3) chinese = 3C3 × [3C0 + 3C1 + 3C2 + 3C3] = 1 × [8]
Total sets = 8× (3+3+1) = 56