How large of a disk can this file system support

Question

Answer 1

12 direct pointers can address 12*2048B = 12*2*1KB= 24KB

A single indirect pointer can point 2048*8/32 blocks = 2048*8*2048/32 = 1MB

A double indirect pointer can point 2048*8*2048*8/32*32 blocks = 2048*8*2048*8*2048/32*32 = 0.5GB

similarly triple will be 2048*8*2048*8*2048*8*2048/32*32*32 = 256 GB

answer is A

Comments

@pavan can you throw some light on how you are calculating single indirect , double indirect and triple indirect pointer can point??