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A computer receives a time stamp request from another computer at 2 : 34 : 20 P.M. The value of original time stamp is 52,453,000 (milli second). If sender clock is 5 milli second slow, the one-way time is___________ (ms)

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2: 34:20 PM  = 14*3600 +34*60+20 = 52460 sec = 52460,000 milli sec ( 2 PM = 14 hrs)

computer  time stamp : 52,460,000

original time stamp  : 52,453,000

time difference = 7000 milli sec

sender clock delay  is 5 milli second slow(given)

Total one-way time =7000 +clock delay =7005 (Answer)

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