We can also solve it in less time using the characteristic equation of D and T flip flop.
We denote T FF output by Q1 and D FF output by Q0.
Now , Q1N = Q1 EXOR T = Q1 EXOR Q0
and Q0N= D = Q1
Initailly Q1=Q0=1
Q1 Q0 Q1N Q0N
1 1 0 1 1st clock cycle
0 1 1 0 2nd
1 0 1 1 3rd
1 1 0 1 4th
Hence the answer - 11,O1 option B