1 votes 1 votes L1={a^nb^m, n=>4,m<=3 L1=(aa)*(bb)*+a(aa)*b(bb)* Find L1 complement? gabbar asked Feb 19, 2017 gabbar 337 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes (Epsilon+a+aa+aaa)bbbb^n where n=>3 arch answered Feb 19, 2017 arch comment Share Follow See all 2 Comments See all 2 2 Comments reply gabbar commented Feb 19, 2017 reply Follow Share Regular expression will be aaaaa*(lemda +b+bb+bbb) 0 votes 0 votes arch commented Feb 19, 2017 reply Follow Share this is the re for L1 but question is find d complement. i think complement of L1 will be (Epsilon+a+aa+aaa)bbbb^n where n=>3 0 votes 0 votes Please log in or register to add a comment.