in Calculus edited by
1,061 views
0 votes
0 votes
The approximate value of y(0.1) from dy/dx = $x^2$y-1, y(0) =1 is

(a) 0.900

(b) 1.001

(c) 0.802

(d) 0.994
in Calculus edited by
by
1.1k views

1 Answer

0 votes
0 votes
By solving using Euler's method. $x_0 = 0, y_0 = 1, x_1 = 0.1$

At $(x_0, y_0)$, $\frac{dy}{dx} = x^2y - 1 = -1$.

Now, $\frac{dy}{dx} \approx \frac{y_1 - y_0}{x_1 - x_0}$.

On putting values, you get $y_1 = 0.9$.

Hence, D = $0.9$ is the answer.

1 comment

May you please give ref link to know about Euler's method.
0
0
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true