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ISRO 2012- [Mech] Calculus
sh!va
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Calculus
Mar 7, 2017
edited
Mar 8, 2019
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Naveen Kumar 3
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The approximate value of y(0.1) from dy/dx = $x^2$y-1, y(0) =1 is
(a) 0.900
(b) 1.001
(c) 0.802
(d) 0.994
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By solving using Euler's method. $x_0 = 0, y_0 = 1, x_1 = 0.1$
At $(x_0, y_0)$, $\frac{dy}{dx} = x^2y - 1 = -1$.
Now, $\frac{dy}{dx} \approx \frac{y_1 - y_0}{x_1 - x_0}$.
On putting values, you get $y_1 = 0.9$.
Hence, D = $0.9$ is the answer.
Gaurav Sharma
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Mar 10, 2017
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Gaurav Sharma
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May you please give ref link to know about Euler's method.
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