0 votes 0 votes The approximate value of y(0.1) from dy/dx = $x^2$y-1, y(0) =1 is (a) 0.900 (b) 1.001 (c) 0.802 (d) 0.994 Calculus engineering-mathematics isro-mech calculus + – sh!va asked Mar 7, 2017 • edited Mar 8, 2019 by Naveen Kumar 3 sh!va 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes By solving using Euler's method. $x_0 = 0, y_0 = 1, x_1 = 0.1$ At $(x_0, y_0)$, $\frac{dy}{dx} = x^2y - 1 = -1$. Now, $\frac{dy}{dx} \approx \frac{y_1 - y_0}{x_1 - x_0}$. On putting values, you get $y_1 = 0.9$. Hence, D = $0.9$ is the answer. Gaurav Sharma answered Mar 9, 2017 Gaurav Sharma comment Share Follow See 1 comment See all 1 1 comment reply Shubhanshu commented Sep 8, 2017 reply Follow Share May you please give ref link to know about Euler's method. 0 votes 0 votes Please log in or register to add a comment.