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2 Answers

3 votes
3 votes
P(A)=.2

P(B)=.3

$P(A\cap B)=P(A)*P(B)=.2*.3=.06$

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$=.2+.3-.06$

$=.44$
edited by
1 votes
1 votes
Option C is Correct.

P(A¯) = 0.2

P(A) = 1−0.2 = 0.80

P(B¯)=0.3

P(B) = 1−0.3 = 0.7

P(A¯∪B¯)= $P(\overline{A\cap B})$ =1−P(A∩B)     =   1−P(A)P(B) =1−(0.8)(0.7)

=0.44

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