In the following problem first, we have a parabola ($y^{2}= 4ax$) and the equation of a straight line given by ($y = mx + c$). We see the graph comes like this.
So , now let us equate the 2 equations:
$x + 2 = 3\sqrt{x}$
$(x + 2) ^{^{2}}= 9x$
$x^{^{2}} - 5x + 4 = 0$
By simplifying this quadratic equation we get $x = 4$ and $x = 1$ .
Similarly, substitute the values of x in the equation, we get $y = 6$ and $y = 3$.
Now by using Integration, we solve the problem
Area bounded by 2 curves is given by area bounded by the parabola - Area bounded by the St Line