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ISRO 2013- Newton Raphson [EE]

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The equation $x^3$ - $x^2$ + 4$x$ - 4 = 0 is to be solved using the Newton - Raphson method. If x =2 is taken as the initial approximation of the solution, then the next approximation using the method will be

a) 2/3

b) 4/3

c) 1/3

d) 5/3
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f(X)=X3-X2+4X-4

f`(X)=3X2-2X+4

f(X0)=8   f`(X0)=12       (X0=2)

X1=2-$\frac{8}{12}$

X1=4/3

Answer B.

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