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From ax+ bx + c = 0, sum of roots is -(b/a) and product is c/a , in given equation c/a = 12 = product of roots and one of them is 4 so other has to be 3. And p = -7.

Now second equation becomes x-7x + q=0. Let a and b be the roots. Given ab = q and a+b =7. Now a=b, so a2 = q and 2a = 7 and a = 7/2 which gives q = 49/4 (option A)

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