1 votes 1 votes The solution of the differential equation (d y /dx)=ky , Y(0)= C is (a) x =ce-xy (b) y= cekx (c) x =ke cy (d) y= ce-kx Calculus isro-ee engineering-mathematics calculus + – sh!va asked Mar 10, 2017 • edited Mar 6, 2019 by Naveen Kumar 3 sh!va 998 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes (1/y) dy = kdx Now integrate the equation which gives log y = kx + c' log y = kx + log c ( c'= log c) y = e(kx +log c) = cekx (option B) Rahul Jain25 answered Mar 10, 2017 Rahul Jain25 comment Share Follow See all 0 reply Please log in or register to add a comment.