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$\begin{align*} x &= i\\ &= cos\frac{\pi}{2} + i.sin\frac{\pi}{2}\\ &= e^{i.\frac{\pi}{2}}\\ x^x& = (e^{i.\frac{\pi}{2}})^i\\ & = e^{-\frac{\pi}{2}} \end{align*}$

Hence, A is the answer.

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A is the answer

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