1 votes 1 votes Find out the generating function for $S_n = 1^2 + 2^2 + 3^2 + 4^2 + ... n^2$ and with that generating function show that it is equal to $\begin{align*} \frac{n\left ( n+1 \right )\left ( 2n+1 \right )}{6} \end{align*}$ Find out the generating function for $S_n = 1^3 + 2^3 + 3^3 + 4^3 + ... n^3$ and with that generating function show that it is equal to $\begin{align*} \left ( \frac{n\left ( n+1 \right )}{2} \right )^2 \end{align*}$ Combinatory discrete-mathematics generating-functions recurrence-relation + – dd asked Mar 15, 2017 retagged Jun 4, 2017 by Arjun dd 376 views answer comment Share Follow See 1 comment See all 1 1 comment reply Gurdeep Saini commented Nov 9, 2018 reply Follow Share https://math.stackexchange.com/questions/1604414/sum-of-squares-using-generating-functions proof of first part 0 votes 0 votes Please log in or register to add a comment.