0 votes 0 votes S -> AA | B A-> BB | S B-> c | ab Theory of Computation theory-of-computation + – LavTheRawkstar asked Mar 16, 2017 LavTheRawkstar 1.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes S -> AA | B A-> BB | S B-> c | ab solution: S -> B, A->S are two Unit production in order to remove it: S -> AA | c |ab A -> BB | AA | c | ab B -> c | ab I m not sure about it.....plz confirm akash.dinkar12 answered Mar 16, 2017 akash.dinkar12 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes S-->AA|c|ab A-->BB|AA|c|ab B-->c|ab Purvi Agrawal answered Mar 16, 2017 Purvi Agrawal comment Share Follow See all 0 reply Please log in or register to add a comment.