0 votes 0 votes A class is composed of 2 brothers and 6 other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated together? kamboj asked Mar 16, 2017 kamboj 670 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes total number of waysin wich we can arrange 8 boys =7! (as it is a round table,so (n-1)! number of ways in which 2 brothers sit together = 6!*2 therefore,required ways are 7! - 2*6! Akriti sood answered Mar 16, 2017 edited Mar 16, 2017 by Akriti sood Akriti sood comment Share Follow See all 2 Comments See all 2 2 Comments reply kamboj commented Mar 16, 2017 reply Follow Share answer given is: 3600 0 votes 0 votes Akriti sood commented Mar 16, 2017 reply Follow Share pls check now,i missed that table is circular 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes First place the 6 boys at a round table in a round table among 6 boys there would be 6 places among these 6 places 2 brother can be made to sit in 6P2 ways and 6 boys can be made to seat in round table in (n-1)! Ways so 5! Therefore total ways equal to 6P2×5! Comes out to be 3600 Kaluti answered Mar 17, 2017 Kaluti comment Share Follow See all 0 reply Please log in or register to add a comment.