YES, Since friendship is symmetric relation i.e. A->B (A is friend of B) then B->A also (B is friend of A) and lets say A and B both have common friend C then we have A->C, C->A, B->C and C->B, from this { A->B, B->A, A->C, C->A, B->C, C->B} we can infer that it is not transitive relation.