Question

In a certain communication channel ,the signal power is 100 W and noise power is 10 W in order to send information at the rate of 10 kbps ,what is require bandwidth ?

Answer 1

signal power is 100 W

noise power is 10 W

 data rate of 10 kbps

Bandwidh?

Max data rate = bandwidth * log (1 + (Siginal power / Noise power))

          10 = bandwidth * log (1 + (100 / 10))   {   log (1 + (100 / 10))  = 3.4594 approx. equal to 4 is taken here}

           10 = bandwidth * 4

bandwidth = 2.5 Kbps