mean number of transmissions -
p + (1-p)p +(1-p)p^2..........
so thee above is the probability but not the mean of no of transmissions mean of no of transmissions will be
3+6+9+12+..............................................
3(1+2+3+............................)
3(n(n+1)/2)
asit is mean we need to divide with no of transmissions so it whould be
(3n+3)/2
according to me option A and option C are similar hops a packet makes per transmission? (which means no of hops for a succesful transmission )
(c) hops required per received packet this also mean the same that is 3