c programming closed

Question

explain the output

#include <stdio.h>
int main()
{
 
    int a=1;
    printf("%d %d %d",a,a++,--a);
     return 0;
     
 }

Comments

1 1 0

---

Output is  101

In the case of print() pre and post operations values update after print initial value

Print() calculate from right to left.

First --a means it prints 1 and decrement for next

Now a=0

Second a++

Print 0 and increment for next

Now a=1

Print 1

So output is 101

Answer 1

These kinds of expressions are compiler dependent....

 printf("%d %d %d",a,a++,a--);

 printf("%d %d %d",a,a++,--a);

Both will give some output which will be 1 0 1

It might be possibility if we run these statement in different compilers, these may give different output...