retagged by
523 views
1 votes
1 votes
what will be the output of following program ?

would this program compile properly ?

#include  <stdio.h>

void swap(int **cc,int *dd)
{
int t=**cc;
    **cc=*dd;
    *dd=t;
}

void exchange(int *cc,int *dd)
{
swap(&cc,dd);
}
int main(void)
{
    int c=10,d=20;
    printf("befor swap c=%d  d=%d \n",c,d);
    exchange(&c,&d);
    printf("after swap c=%d  d=%d \n",c,d);
}
retagged by

5 Answers

0 votes
0 votes

Yes program will work...U can relate pointers like this :

Related questions

0 votes
0 votes
1 answer
1
SSR17 asked Feb 29
205 views
#include <stdio.h int main() { int i = -1; int x = (unsigned char)i; printf("%d", x); return 0; }output is 255 , but please explain how
2 votes
2 votes
1 answer
2
rupamsardar asked Aug 30, 2023
468 views
#include <stdio.h int f(int x) { if(x%2==0) { return f(f(x-1)); } else return (x++); } int main() { printf("%d",f(12)); ret...
5 votes
5 votes
2 answers
3
saurabh0709 asked Aug 1, 2023
1,136 views
What will be the output of the following code? _______ #include <stdio.h int main(){ char val=250; int ans; ans= val+ !val + ~val + ++val; printf("%d", ans); return 0; }
2 votes
2 votes
1 answer
4