ISRO2017-62

Question

What will be the output of the following C code?

#include <stdio.h>
main()
{
    int i;
    for(i=0;i<5;i++)
    {
        int i=10;
        printf("%d" , i);
        i++;
    }
    return 0;
}

• A. 10 11 12 13 14
• B. 10 10 10 10 10
• C. 0 1 2 3 4
• D. Compilation error

Answer 1

include<stdio.h>
main()
{ int i;                    // variable declared with name i 
 for(i=0;i<5;i++)           // loop condition satisfied
 {
   int i=10; //new memory created with variable i and assign 10 to it with scope inside Forloop
   printf("%d" , i);         // print value of i which is declared inside for loop. 
   i++;                      //inner declare i which contain 10 is incremented.
 }
return 0;
}

Note for every time loop condition check with outer declare i and dor every outer declared i every time new variable i  is declared and assign 10 to it .

so output will be 10, 10, 10, 10, 10,

Atlast vlaue of outer i = 5 and inner i = 11

Comments

But C language only supports initialization at the beginning. So wont it be an error

---

but here i is declared twice

will it not give compilation error?

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No, this won't give a compilation error as the second 'i' is declared and initialised inside a 'FOR' block. So it becomes a local variable for the for block only. (There is no typing error in this question.)

Answer 2

Think the answer is OPTION D compilation error.

There are 2 errors in the given program:

1. The header file included is wrong (it must be stdio.h ) which raises reference error.

2. The variable 'in' is undeclared in the program and since C language doesn't support variables without declaration, it raises and error.

Comments

it is typing mistake ...

take "in as i"  and stdio.h ...

since isro can't ask such stupid question at least in c language.

Answer 3

Option B

Comments

how???

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Default return type of main is int and main is returning 0 at the end so correct answer is b. 10 10 10 10 10

Answer 4

b) 10,10,10,10,10